Question

the area of triangle formed by the point p(2,0),q(4,0),r(3,6)​

Answer 1

Answer:

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Answer 2

Answer:

We know that the area of the triangle whose vertices are (x

1

,y

1

),(x

2

,y

2

), and (x

3

,y

3

) is

2

1

∣x

1

(y

2

−y

3

)+x

2

(y

3

−y

1

)+x

3

(y

1

−y

2

)∣

Given P(−1.5,3),Q(6,−2) and R(−3,4)

Therefore, area is given by

=

2

1

×[(−1.5)(−2−4)+6(4−3)+(−3)(3+2)]

=

2

1

×(9+6−15)

=0