Question

The area of triangle formed by vertices (5, 2) (–9, –3) (–3, –5) is

Answer 1

$area \: of \: required \: triangle \: = \: 29 {unit}^{2}$

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Answer 2

The area of triangle is 29 square unit.

Step-by-step explanation:

To find : The area of triangle formed by vertices (5, 2) (–9, –3) (–3, –5) ?

Solution :

The area of the triangle is given by,

$A=\frac{1}{2}[x_1(y_2-y_3)+x_2(y_3-y_1)+x_3(y_1-y_2)]$

Here, $(x_1,y_1)=(5,2),(x_2,y_2)=(-9,-3),(x_3,y_3)=(-3,-5)$

$A=\frac{1}{2}[5(-3-(-5))+-9(-5-2)+-3(2-(-3))]$

$A=\frac{1}{2}[5(2)+(-9)(-7)+(-3)(5)]$

$A=\frac{1}{2}[10+63-15]$

$A=\frac{1}{2}[58]$

$A=29$

Therefore, the area of triangle is 29 square unit.

#Learn more

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