Question

The area of triangle formed with the origin and the point (4,0) and (0,6) is
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Answer 1

Here you go friend: The following attachment contains ur answer

Answer 2

Recall that there are 3 ways to find the area of a triangle:$\text{ Area of a Triangle } = \dfrac{1}{2} \times \text {Base} \times \text{Height}$

$\text{ Area of a Triangle } = \dfrac{1}{2} ab \sin C$

$\text{ Area of a Triangle } = \sqrt{s(s - a)(s - b) (s - c)}$

Given:

The three points are point of origin, (4, 0) and (0.6)

Note that:

The point of origin is the coordinate (0, 0).

See attached for the 3 points plotted.

We can observed that it is a right-angled triangle.

Find the area of the triangle formed:

$\text{ Area of a Triangle } = \dfrac{1}{2} \times \text {Base} \times \text{Height}$

$\text{ Area of a Triangle } = \dfrac{1}{2} \times \text {4} \times \text{6}$

$\text{ Area of a Triangle } = 12 \text{ units}^2$

Answer: Area of the triangle is 12 units²