the area of triangle oab = area triangle poq .find the coordinates of point a
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Answer:
OC= Length of the perpendicular from (0,0) to the line 3x+4y+15=0
⟹OC=
3
2
+4
2
∣0+0+15∣
=
9+16
15
=
5
15
=3
In △OPQ,
OP=OQ
Hence the triangle is isoceles.
⟹OC bisects base PQ. C is the mid point of PQ
In right angle △OCQ
OQ
2
=OC
2
+CQ
2
⟹CQ
2
=9
2
−3
2
⟹CQ=
72
=6
2
As C is the mid point of PQ
⟹PQ=2×6
2
=12
2
Area=
2
1
×base×height=
2
1
×PQ×OC
=
2
1
×12
2
×3
=18
2
(unit)
2
------Option D
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