Math, asked by sushmita45, 8 months ago

The area of triangle PQR having vertices P(0,8),Q(0,0) and R(6,0) is​

Answers

Answered by pandu8282
4

Step-by-step explanation:

From R:(c, d), draw line segment RA perpendicular to the x-axis. Let O denote the origin (0,0).

area ΔPQR = area trapezoid OPRA- area ΔQAR - area ΔOPQ

=

2

1

c(a+d) -

2

1

d(c−b)-

2

1

ab=

2

1

(ac+bd−ab).

If c area ΔPQR = area trapezoid OPRA + area Δ QAR - areaΔOPQ=

2

1

c(a+d)

2

1

d(b−c)−

2

1

ab=

2

1

(ac+bd−ab).

solution

Similar questions