Question

the area of triangle whose sides are 13cm,14cm and 15cm .​

Answer 1

Answer:

84 cm^2

Step-by-step explanation:

S =  (a + b + c)/2

  = (13 +14+15)/2

 = 42/2

   =21

A= sq root (

s(s-a)(s-b)(s-c))

 = sq root (21(21-13)(21-14)(21-15)

 = sq root (21 x 8 x 7 x 6 )

 =sq root (7056)

 = 84 cm^2

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Answer 2

Answer:

$area = \sqrt{s(s - a)(s - b)(s - c }$

$= \sqrt{21(21- 13)(21 - 14)(21- 15}$

$\sqrt{21 \times 8\times 7 \times 6}$

$= \sqrt{7056}$

$= 84$

$= 84 cm^2$

Let me know if the calculations are wrong

Step-by-step explanation:

the square root of the product s(s – a)(s – b)(s – c) where s is the semiperimeter of the triangle, that is, s = (a + b + c)/2.