The area of triangle, whose sides are 15 cm, 25 cm and 14 cm is
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HOWDY MATE
Here's Your answer.
Let
a = 15cm
b = 25cm
c = 14cm
Semi-Perimeter = a + b + c / 2
= 15 + 25 + 14 / 2
= 54 / 2
= 27 cm.
Area Through Heron's Formula
= √s(s-a)(s-b)(s-c)
= √27(27-15)(27-25)(27-14)
= √27 × 12 × 2 × 13
= √3 × 3 × 3 × 2 × 2 × 3 × 13
= 3 × 3 × 2 √13
= 18 √13
= 18 × 3.60
= 64.8cm^2
Have a Great day
^_^
Here's Your answer.
Let
a = 15cm
b = 25cm
c = 14cm
Semi-Perimeter = a + b + c / 2
= 15 + 25 + 14 / 2
= 54 / 2
= 27 cm.
Area Through Heron's Formula
= √s(s-a)(s-b)(s-c)
= √27(27-15)(27-25)(27-14)
= √27 × 12 × 2 × 13
= √3 × 3 × 3 × 2 × 2 × 3 × 13
= 3 × 3 × 2 √13
= 18 √13
= 18 × 3.60
= 64.8cm^2
Have a Great day
^_^
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