Question

the area of triangle whose sides are 4 cm,13 cm,15 cm is​

Answer 1

Step-by-step explanation:

24 cm ² will be the answer .

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Answer 2

GIVEN:

• sides of the triangle = 4 , 13 and 15cm

TO FIND:

area of the triangle

SOLUTION:

it is given that,

the side of the triangle are 4, 13 and 15cm

${\underline{\pink{\sf{ using\: heron's\:formula}}}}$

${ \boxed {\purple{ \sf {area \: of \: triangle \: = \sqrt{s(s - a)(s - b)(s - c)} }}}}$

$\sf \: where \: \: s = \frac{a + b + c}{2}$

$\sf \rightarrow \: s \: = \frac{4 + 13 + 15}{2}$

$\rightarrow\sf{s\: =\: 16cm}$

NOW,

$\sf \rightarrow area \: of \: the \: triangle \: = \sqrt{16(16 - 4)(16 - 13)(16 - 15)}$

$\rightarrow\sf \: area \: of \: the \: triangle \: = \sqrt{16 \: \times \: 12 \: \times 3 \: \times 1 }$

$\rightarrow\sf{4 \: \times \: 6}$

$\rightarrow\sf{24cm^2}$

HENCE,

the area of the triangle is 24cm²