Question

the area of triangle whose sides are 5 cm and 13 cm and 12 CM by using heron's formula​

Answer 1

Answer:

In ∆ ABC ...

Given, AB =5 cm

BC = 12 cm

A = 13 cm

5 ^2 + 12^2 =13^2 ( pythagoras theorem )

Therefore , ∆ ABC is a right angled triangle..

That is ,

area of ∆ ABC = 1/2 × b × h

= 1/2 ×5 ×12

= 30 cm ^2.

Answer 2

Answer:

30 sq cm

Step-by-step explanation:

By heron's formula

s=(a+b+c)/2

=(5+12+13)/2

=30/2=15

Area of triangle=root s×(s-a)(s-b)(s-c)

=root 15×(15-5)(15-12)(15-13)

=root 15 ×10 ×3 ×2

=root 5×3×2×5×3×2

=5×3×2=30 sq cm