Question

The area of triangle whose sides is 18cm 10 cm and 14 cm

Answer 1

Answer:

$s =(a + b + c ) \div 2 \\ (10 + 14 + 18) \div 2 = 21$

heron's formula

$area = \sqrt{s(s - a)(s - b)(s - c)}$

area=

$\sqrt{21(21 - 10)(21 - 14)(21 - 18)}$=69.64cm²

Answer 2

Answer:

apply herons formula

s=

[tex]s = \frac{(a + b + c)}{2} = \frac{21}{2} = 21 \\ \\ area = \sqrt{21(21 - 18)(21 -