The area of triangle whose vertices are (1,-1),(2,1) and (4,5)is
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Given that, the coordinates of the vertices of a triangle are (1,−1),(−4,6),(−3,−5)
Let us Assume A(x1,y1)=(1,−1), B(x2,y2)=(−4,6) and C(x3,y3)=(−3,−5)
We know that,
Area of triangle =21[x1(y2−y3)+x2(y3−y1)+x3(y1−y2)]
Therefore,
Area of the given triangle =21[{1(6−(−5))}+{(−4)(−5−(−1))}+{(−3)((−1)−6)}]
⇒21{11+16+21}
⇒248=24 square units
Hence, the area of the triangle with given vertices is 24 square units
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