the area of triangle whose vertices are (5,1) ,(1,-1) and (11,4) is
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Answered by
1
1/2 [ 5 1 1 ] its called matrices
1 -1 1
11 4 1
or 1/ 2[ x1( y2 - y3) + x2 ( y3 - y1) + x3 ( y1 - y2 ) ]
1 -1 1
11 4 1
or 1/ 2[ x1( y2 - y3) + x2 ( y3 - y1) + x3 ( y1 - y2 ) ]
Answered by
1
taking (5,1) as a main point
then (1,-1) will change to (-4,-2)
and (1,-1) will change to (6,3)
using vectors ,
A= -4i + (-2)j
B= 6i + 3j
|A×B|/2 = area of triangle
i don't have any paper with me now
but this method is a great one do try
then (1,-1) will change to (-4,-2)
and (1,-1) will change to (6,3)
using vectors ,
A= -4i + (-2)j
B= 6i + 3j
|A×B|/2 = area of triangle
i don't have any paper with me now
but this method is a great one do try
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