the area of triangle whose vertices are a(0,2)B(2,0) andc(0,4)
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Answer:
Step-by-step explanation:
if you try to plot the points roughly
you will find that the height of triangle is 2 unit (2,0)
and the base of triangle is also 2 units (4-2,0-0)
so area = 1/2 × base × height
= 1/2 ×2×2
= 2 unit square
Answered by
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Step-by-step explanation:
if we plot we get,,
1. the distance from the origin and the point B(2,0)
is 2 unit (height,, lies on x-axis)
2.the distance from the point A(0,2) to the point c(0,4) is 2 unit (base,,lies on y-axis)
so the area of the ∆ABC will be 1/2 ×2 ×2 sq.unit =2 sq.unit
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