The area of triangle with given two sides 18 cm & 10 cm respectively and perimeter equal to
42 cm is
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Answer:
Did you mean: The area of triangle with given two sides 18 cm and 10cm respectively and perimeter equal to 42 cm is
The area of triangle with given two sides 18 cm and 10 cm respectively and perimeter equal to 42 cm is: a. 20 √11 cm2
Step-by-step explanation:
Area = 21√11 cm²
Step-by-step explanation:
Given:
Perimeter of triangle is 42 cm.
Measure of two sides of triangle are 18 and 10 cm respectively.
Solution: Let the third side of triangle be x cm. Therefore,
➯ Sum of all sides = Perimeter
➯ 18 + 10 + x = 42
➯ x = 42 – 28
➯ x = 14 cm { Third sides of triangle }
Now, For finding area of ∆ we will use Heron's Formula.
First find the Semi-Perimeter (s)
➬ s = (Sum of all sides / 2)
➬ s = (42/2)
➬ s = 21
Formula = √s(s–a) (s–b) (s–c) (Herons formula)
√21 (21 – 18) (21 – 10) (21 – 14)
=√21 (3) (11) (7)
= √3 × 7 × 3 × 11 × 7
= 3 × 7 √11
= 21√11 cm²
Hence, the area of triangle is 21√11 cm².
Hope helps