Math, asked by neetupreet890, 17 hours ago

The area of triangle with given two sides 9cm and 5 cm respectively and perimeter equal to 22 cm is:
(2 Points)​

Answers

Answered by vsnaik
0

Answer:

hi

Step-by-step explanation:

Answer

Let the sides of triangle be a,b,c

Given one side is a=9 cm

Perimeter of triangle is 2s=22 cm

⟹a+b+c=22

⟹b+c=22−9

⟹b+c=13⋯(1)

Difference between the two sides is 3 cm

⟹b−c=3⋯(2)

(1)+(2)⟹b+c+b−c=13+3⟹2b=16⟹b=8

Substituting b=8 in (1)

⟹8+c=13⟹c=5

As we know that

Area of triangle with sides a,b,c is

s(s−a)(s−b)(s−c)

2s=22⟹s=11

So area is

11×(11−9)×(11−8)×(11−5)

=

11×2×3×6

=6

11

cm

2

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