The area of triangle with given two sides 9cm and 5 cm respectively and perimeter equal to 22 cm is:
(2 Points)
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Step-by-step explanation:
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Let the sides of triangle be a,b,c
Given one side is a=9 cm
Perimeter of triangle is 2s=22 cm
⟹a+b+c=22
⟹b+c=22−9
⟹b+c=13⋯(1)
Difference between the two sides is 3 cm
⟹b−c=3⋯(2)
(1)+(2)⟹b+c+b−c=13+3⟹2b=16⟹b=8
Substituting b=8 in (1)
⟹8+c=13⟹c=5
As we know that
Area of triangle with sides a,b,c is
s(s−a)(s−b)(s−c)
2s=22⟹s=11
So area is
11×(11−9)×(11−8)×(11−5)
=
11×2×3×6
=6
11
cm
2
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