The area of triangle with given two sides and respectively and perimeter equal to is:
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Answered by
3
Answer:
Two sides length are given, we need to figure out the length of this side.
⇒Let x be length of third side
⇒Perimeter =42 cm
⇒18+10cm+x=42
⇒x=42−28=14 cm
⇒2s=42
⇒s=21 cm
⇒a=18,b=10,c=14
⇒A=
s(s−a)(s−b)(s−c)
⇒
21(21−18)(21−10)(21−14)
=
21×3×11×7
⇒A=21
11
cm
2
Answered by
1
Answer:
Area of the ∆ = 21√11 cm²
Step-by-step explanation:
Refer to the image.
Hope it helps!!
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