Question

The area of triangle with sides 11cm , 15cm , 10cm is

Answer 1

Answer:

area of triangle using heroines formula = √s(s-a)*(s-b)*(s-c) = a+b+c/2

√s(s-11)*(s-15)*(s-10)

11+15+10/2 = 18

√18(18-11)*(18-15)*(18-10)

√18*7*3*8

Answer 2

Given:- sides of triangle are 11cm, 15cm and 10cm.

To find:-

• Area of traingle.

Solution :-

$\sf \: s = \dfrac{11 + 15 + 10}{2} = \dfrac{36}{2} = 18$

By using Heron's Formula,

$\sf Area \: of \: triangle = \sqrt{s(s - a)(s - b)(s - c)} \\ \sf = \sqrt{ 18(18 - 11)(18 - 15)(18 - 10)} \\ \sf = \sqrt{18(7)(3)(8)} \\ \sf = \sqrt{3024} \\ \sf = \boxed{\sf 54.9cm {}^{2}}$

Hence, area of traingle is 54.9cm².

Extra information:-

Heron's Formula

It is a mathematical formula that can be used to find the area of a triangle, when there's given its three side lengths.

$\sf \sqrt{s(s - a)(s - b)(s - c)}$

Here, S is equal to semi-perimeter of traingle.

$\small \sf \: s = \dfrac{a + b + c}{2}$