Question

the area of triangle with sides 9cm, 4 cm and the 41 cm is 180cm². The altitude to the smallest side is.​

Answer 1

Answer:

the answer iS 24 m

• Hope this. Help you

Answer 2

• As per the data given in the question, we have to determine the altitude to the smallest side of a triangle.

        Given data:- Sides; a=$9cm$, b=$4cm$,c=$41cm.$

                              Area=$180cm^{2}.$

        To find:- the altitude to smallest size(h)=?

        Solution:-

• As we know that,

       The smallest side of the triangle is $4cm.$so we calculate

        Area=$\frac{1}{2}\times$base$\times$altitude.

        Putting the value of triangle in the formula, we get,

        $180=\frac{1}{2}\times4\times$altitude

       altitude=$\frac{180\times2}{4}=90cm.$

  Hence, the altitude to smallest side will be $90cm.$