Question

The area of triangle with vertices (3,0),(7,0) and (8,4) is Sq units

Answer 1

Step-by-step explanation:

It is 12 sq units only. You have to use the triangle area formula in coordinate geometry

Answer 2

The area of the triangle is "8 square units".

Step-by-step explanation:

Given,

The three vertices  of the triangle are (3, 0), (7, 0) and (8, 4).

To find, the area of the triangle = ?

We know that,

The area of triangle

$=\dfrac{1}{2} [x_{1}(y_{2}-y_{3})+x_{2}(y_{3}-y_{1})+x_{3}(y_{1}-y_{2})]$

∴ The area of the triangle

= $\dfrac{1}{2} [3(0-4)+7(4-0)+8(0-0)]$ square units

= $\dfrac{1}{2} [3(-4)+7(4)+8(0)]$ square units

= $\dfrac{1}{2} [-12+28+0]$ square units

= $\dfrac{1}{2} (16)$ square units

= 8 square units

Thus, the area of the triangle is "8 square units".