Question

The area of triangle with vertices (4,0),
(0, 0), (0, -6) is (in sq.units)​

Answer 1

Answer:

A = 1/2 [ x₁(y₂-y₃)+x₂(y₃-y₂)+x₃(y₂-y₁) ]

x₁ = 4 y₁ = 0 x₂ = 0 y₂ = 0 x₃ = 0 y₃ = -6

=> A = 1/2 [ 4(0-(-6) + 0(-6-0) + 0(0-0) ]

=> A = 1/2 [ 4(6) + 0 + 0 ]

=> A = 1/2 * 24

=> A= 12 sq units

Answer 2

Step-by-step explanation:

Given vertices are (4,0),(0,0),(0,6)

We know that(W.K.T),

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Area of ∆=1/2|x1(y2-y3)+x2(y3-y1)+x3(y1-y2)|

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=1/2|[(4)(0-6)]+[(0)(6-0)]+[(0)(0-0)]|

=1/2|(0-24)+(0-0)+(0-0)|

=1/2|-24+0+0|

=1/2|-24|

=|-24/2|

=|-12|

Since area is a measure,which cannot be negative,we will take the numberical value of -12 or absolute value i,.e.,|-12|=12

therefore, the area of triangle=12 square units.