Question

The area of triangle with vertices (4, 0); (1, 1)

and (3, a) is 2 then a = ?

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Answer 1

Answer:

Area of the triangle = 1/2 x1(y2-y3) + x2(y3-y1) + x3(y1-y2)

Here. x1= 4 ; x2=1 ; x3= 3

y1=0 ; y2= 1 y3= a

Putting the values in the formula.

2 = 1/2 4(1-a) + 1(a-0) + 3(0-1)

4 = 4 - 4a + a - 3

4= 1 - 3a

4-1 = - 3a

3 = - 3a

a= - 1