Question

the area of triangle with vertices (5,0), (3,0) and (3/2,0)​

Answer 1

Answer:

Area of Triangle using coordinates of A, B and C

Area =0.5[x

1

(y

2

−y

3

)+x

2

(y

3

−y

1

)+x

3

(y

1

−y

2

)]--------(1)

Here in our case A(5,0)=(x

1

,y

1

)

A(8,0)=(x

2

,y

2

)

A(8,4)=(x

3

,y

3

)

Substituting above values in Eq - 1, we get

Area =0.5[5(0−4)+8(4−0)+8(0−0)]

Area =0.5[−20+32]

Area =0.5×(12)=6

Area=6 units

Answered By

toppr

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