the area of two equal circles in the figure is 308 CM square find the perimeter of the rectangle
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Step-by-step explanation:
=> Given:
=> Area of two equal circule is 2×pir²
=> 2×22/7×r×r = 308
=> r² = 308/2×7/22
=> r² = 49
=> r = √49 = 7cm
Now,
=> 2r = diameter of circule = length of rectangle
=> length = 14
=> radius of circule = breadth of rectangle = 7cm
=> °.°Perimeter of rectangle = 2(l+b)
=> = 2(14+7)
=> =2×21 => 42cm
=> .°. The perimeter of rectangle is 42cm.
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