Question

The area of two equal circles in the figure is 308 Sq.m . find the perimeter of the rectangle.

Answer 1

Area of two circle =308m2
Area of one circle =308/2=154m2
AREA Of circle =22/7*r2
154=22/7*r2
154*7/22=r2
7*7=r2
49=r2
7m=r
Diameter of circle=breadth of circle
2*r=breadth
2*7=breadth
14m=breath
We have two circles so length is 2 of diameter
Length =2*14
Length =28m
Perimeter of rectangle =2(l+b)
P=2(28+14)
P=2*42
P=84m

Answer 2

The perimeter of the rectangle is 84 m

Step-by-step explanation:

Area of circle = $\pi r^2$

let the radius of two equal circles  be R

So, Area of two equal circle = $2 \pi R^2$

We are given that The area of two equal circles in the figure is 308 Sq.m

So, $2 \pi R^2=308$

$2 \times \frac{22}{7} R^2=308$

$R^2=\frac{308 \times 7}{2 \times 22}$

$R=\sqrt{\frac{308 \times 7}{2 \times 22}}$

$R=7$

So, Diameter of each circle = $2R=2(7) = 14 m$

Length of rectangle = Diameter of circle 1 + Diameter of circle 2 = 14+14 = 28 m

Breath of rectangle = Diameter of one circle = 14 m

Perimeter of rectangle =$2(l+b)=2(28+14)=84 m$

Hence the perimeter of the rectangle is 84 m

#Learn more :

The area of two equal circles in the figure is 308 Sq.m. find the perimeter of the rectangle.

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