The area of two isosceles traingle are in ratio 16:25 .the ratio of their corresponding heights is
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Answered by
4
AB=AC (given)
∴
AC
AB
=1−(1)
DE=DF (given)
DF
DE
=1−(2)
comparing(1)&(2)
AC
AB
=
DF
DE
⟹
DE
AB
=
DF
AC
In △ABC & △DEF
DE
AB
=
DF
AC
⟹∠A=∠D
∴ By using SAS similar condition
△ABC∼△DEF
ar(△DEF)
ar(△ABC)
=
DQ
2
AD
2
∴ The area of two similar △les are in the ratio of the square of the corresponding altitude.
25
16
=
DQ
2
AP
2
⟹
DQ
AP
=
5
4
Answered by
0
According to similarity,
- Area of corresponding heights is the area of triangle.
- √(16/25)=ratio of their heights
- Therefore,
- ratio of corresponding heights=4/5.
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