The area of two quadrant of diameter 21m
Answers
Answered by
0
Answer:
346.5cm2
Step-by-step explanation:
Given that r=21cm, θ=90∘
Perimeter =(2π+2)r=(7×222+2)×21=75cm
Area=360o90o×4πr2=7×422×21×21=346.5cm2
Answered by
0
Answer:
346.5cm2
Explaination:
Given that r = 2 21cm, 0-90°
Perimeter =(2T+2)r=(7×222+2)x21=75cm
Area 3600900×4πr2-7x422×21×21-346.5cm 2
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