Math, asked by sandhaghunguru, 20 days ago

The area of two quadrant of diameter 21m

Answers

Answered by nitin63348
0

Answer:

346.5cm2

Step-by-step explanation:

Given that r=21cm, θ=90∘

Perimeter =(2π+2)r=(7×222+2)×21=75cm

Area=360o90o×4πr2=7×422×21×21=346.5cm2

Answered by jhakashish251
0

Answer:

346.5cm2

Explaination:

Given that r = 2 21cm, 0-90°

Perimeter =(2T+2)r=(7×222+2)x21=75cm

Area 3600900×4πr2-7x422×21×21-346.5cm 2

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