Question

the area of two semicircles is in the ratio of 49:25. find the ratio of their circumferences.

Answer 1

Heya.....

Your answer is in pic.....

Thanks...!!!

XD

Sorry baby 'wink'

Answer 2

Hey there !!

Let the radius of two semicircles be $r_1$ and $r_2$ .


→ Given :-

▶ The ratio of areas of two semicircles = 49:25 .



$= > \frac{a_1}{a_2} = \frac{49}{25} . \\ \\ = > \frac{ \frac{ \cancel\pi {r_1}^{2} }{ \cancel2} }{ \frac{ \cancel\pi {r_1}^{2} }{ \cancel2} } = \frac{49}{25} . \\ \\ = > {( \frac{r_1}{r_2}) }^{2} = \frac{49}{25} . \\ \\ = > \frac{r_1}{r_2} = \sqrt{ \frac{49}{25} } . \\ \\ = > \frac{r_1}{r_2} = \frac{7}{5} .$


→ To find :-

▶ The ratio of their circumference.


$\therefore \frac{c_1}{c_2} \\ \\ = \frac{ \cancel\pi r_1}{ \cancel\pi r_2} . \\ \\ = \frac{r_1}{r_2} . \\ \\ = \boxed{ \green{ \frac{7}{5} .}}$



✔✔ Hence, ratio of their circumference is 7 : 5 . ✅✅


THANKS



#BeBrainly.