Question

the area of two similar triangle ABC and PQR are in the ratio9:16.if BC =2,cm find QR

Answer 1

If BC and QR are the bases of given triangle
by the properties of areas of similar triangle
area of (ABC)/area of (PQR)=BC/QR
9/16=2/QR
9QR=16×2
QR=32/9
QR=3.55...
QR=3.5cm
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