Question

the area of two similar triangles are 100 square cm and 64 sq cm.of the altitude of smaller triangle is 4cm . then altitude of the bigger one is​

Answer 1

Step-by-step explanation:

Given area of two similar triangles are 100 sq cm and 64 sq cm

The areas of two Similar-Triangles are in the ratio of the squares of the corresponding medians

The ratio of area of triangle =

64

100

=

16

25

Median of greater triangle is 13 cm and let other median is x cm

∴

(x)

2

(13)

2

=

16

25

⇒

x

2

169

=

16

25

⇒25x

2

=169×16

⇒x

2

=

25

2704

=108.16

⇒x=10.4cm