Question

the area of two similar triangles are 100cm and 49cm respectively if the altitude of the smallest triangle is 3.5cm then the corresponding altitude of the smallest triangle is 3.5cm then the corresponding altitude of the bigger triangle is

Answer 1

Answer:

The ratio of the areas of two similar triangles is equal to the square of the ratio of their corresponding altitudes.

The area of two similar triangle are 100cm

2

and 49cm

2

respectively.

The altitude of the bigger triangle is 5cm

Let the altitude of the smaller triangle be x.

Therefore

49

100

=

x

5

7

10

=

x

5

x=3.5cm

The altitude of the smaller triangle is 3.5cm.

Answer 2

Answer:

5 cm

Step-by-step explanation:

Area of two trigangles=100cm and 49 cm

Ratio of Area of two trigangles=100:49=10:7

Now,

Altitude of smaller triangle=3.5

Altitude of bigger triangle=x

Using the ratio,(Since the triangles are similar)

10Altitude of smaller triangle=7Altitude of bigger triangle

10*3.5=7Altitude of bigger triangle

35=7Altitude of bigger triangle

35/7=Altitude of bigger triangle

Therefore, Altitude of bigger triangle=5 cm