Question

the area of two similar triangles are 144 CM ^2 and 81 cm ^2 respectively. if the altitude of the bigger triangle is 6 cm ,find the corresponding altitude of the other​

Answer 1

Answer:

altitude of smaller triangle is 4.5cm

Step-by-step explanation:

area of bigger triangle = 144

area of smaller triangle = 81

altitude of bigger triangle = 6

altitude of smaller triangle = x

ratio of square of altitudes of triangle is equal to the areas of the triangle

$\frac{ {x}^{2} }{ {6}^{2} } = \frac{81}{144} \\ {x}^{2} = \frac{81 \times 36}{144} \\ {x}^{2} = \frac{81}{4} \\ {x}^{2} = 20.25 \\ x = \sqrt{20.25} \\ x = 4.5$