The area of two similar triangles are 49 cm square and 81 cm square,find the ratio of their perimeter
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The ratio of their perimeter will be 7:9 .
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area ΔABC = 1/2 * base * height
In similar triangles, base1 / base2 = height1 / height2 = side1/ side2 (of the three corresponding sides).
Also Area1 / Area2 = (altitude1 / altitude2 )^2
Ratio of altitudes = square root( 81/49) = 9/7 > 1
Altitude of smaller triangle = 4.5 / (9/7) = 3.5
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