Question

the area of two similar triangles are 81 cm square and 49 cm square respectively if the altitude of the first triangle is 6.3 cm find the corresponding altitude of the other

Answer 1

4.9cm.
$\frac{ \sqrt{81} }{ \sqrt{49} } = \frac{6.3}{x} \\ \frac{9}{7} = \frac{9 \times 0.7}{x} \\ x = 4.9cm.$

Answer 2

Answer: x = 4.9cm

Step-by-step explanation: For the procedure, see the image below