the area of two similar triangles are 81 cm square and 49 CM square respectively the altitude of the bigger triangle is 4.5 cm find the corresponding altitude of the smaller traingle
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let corresponding altitude be x
so 81/49=4.5^2/x^2
x^2= 49 x 20.25/81
x^2=12.25
x=3.5cm
so 81/49=4.5^2/x^2
x^2= 49 x 20.25/81
x^2=12.25
x=3.5cm
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BhaktighongateVirtuoso
let corresponding altitude be x
so 81/49=4.5^2/x^2
x^2= 49 x 20.25/81
x^2=12.25
x=3.5cm
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