Question

the area of two similar triangles are 81 cm square and 49 CM square respectively the altitude of the bigger triangle is 4.5 cm find the corresponding altitude of the smaller traingle

Answer 1

let corresponding altitude be x 
so 81/49=4.5^2/x^2
   x^2= 49 x 20.25/81
  x^2=12.25
x=3.5cm

Answer 2

Answer:

Step-by-step explanation:

BhaktighongateVirtuoso

let corresponding altitude be x

so 81/49=4.5^2/x^2

x^2= 49 x 20.25/81

x^2=12.25

x=3.5cm