the area of two similar triangles are 9 square.m and 36 Square. m respectively. lf the height of the one triangle is 24 m, then the height of the other one is
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Hiii friend,
Let ∆ABC and ∆DEF are two similar triangles.
Area of ∆ABC = 9 m²
Area of ∆DEF = 36 m²
Height of one triangle = 24 m
We know that,
The ratio of areas of two similar triangles is equal to the square of the ratio of their heights.
Therefore,
Area of ∆ABC / Area of ∆DEF = Height of one triangle/Height of other triangle.
9/36 = (24/Height of other triangle)²
Height of other triangle² = 576 × 36/9
Height of other triangle² = 2304
Height of the other triangle = ✓2304 = 48
Hence,
The height of other triangle = 48 m
HOPE IT WILL HELP YOU.... :-)
Let ∆ABC and ∆DEF are two similar triangles.
Area of ∆ABC = 9 m²
Area of ∆DEF = 36 m²
Height of one triangle = 24 m
We know that,
The ratio of areas of two similar triangles is equal to the square of the ratio of their heights.
Therefore,
Area of ∆ABC / Area of ∆DEF = Height of one triangle/Height of other triangle.
9/36 = (24/Height of other triangle)²
Height of other triangle² = 576 × 36/9
Height of other triangle² = 2304
Height of the other triangle = ✓2304 = 48
Hence,
The height of other triangle = 48 m
HOPE IT WILL HELP YOU.... :-)
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