Question

the area of two similar triangles are respectively 9 CM square and 49 CM square the ratio of the corresponding sides​

Answer 1

here is ur solution.....

Answer 2

$Given \: the \:area \:of \:two \: similar$

$triangles \: are \: 9\:cm^{2} \:and \: 49\:cm^{2}$

$respectively$

/* We know that , */

$\blue{( The \: ratio \:of \:the \:area \:of \:two}$

$\blue{ similar \: triangles \:is \: equal \:to \:the }$

$\blue{ ratio \:of \:the \:square \:of \:any \:two}$

$\blue{ corresponding \: sides )}$

$\red{Ratio \:of \: corresponding \:sides }$

$=\sqrt{ \frac{9}{49}}$

$= \sqrt{ \Big(\frac{3}{7}\Big)^{2}}$

$= \frac{3}{7}$

$= 3 : 7$

Therefore.,

$\red{Ratio \:of \: corresponding \:sides }$

$\green {= 3 : 7}$

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