Question

the area of two similar triangles ase 25sq.cm and 121 sq. cm .Find ratio of there corresponding sides

Answer 1

$\frac{√25}{√121}$

$ratio:-\frac{5}{11}$

Answer 2

Answer: The required ratio is $5:11.$

Explanation:  Given that the area of two similar triangles are 25 sq. cm and 121 sq. cm.

We know that

the ratio of area of two similar triangles is equal to the squares of the ratio of two corresponding sides.

Let, 'a' cm and 'b' cm be the lengths of the corresponding sides of the two triangles with area 25 sq. cm and 121 sq. cm respectively.

Then, we must have

$\dfrac{25}{121}=\dfrac{a^2}{b^2}\\\\\\\Rightarrow \left(\dfrac{a}{b}\right)^2=\left(\dfrac{5}{11}\right)^2\\\\\\\Rightarrow \dfrac{a}{b}=\dfrac{5}{11}\\\\\\\Rightarrow a:b=5:11.$

Thus, the required ratio of the corresponding sides is 5 : 11.