Question

The area of two similar triangles is 121cm square and 49cm square respectively. If the median of the smaller triangle is 4.2 cm, Find the corresponding median of the other triangle.

Answer 1

Answer:

6.6cm

Step-by-step explanation:

Let the corresponding median of the other triangle be x.

$\frac{area \: of \: triangle \: abc}{area \: of \: triangle \: pqr } = { (\frac{ab}{pq} )}^{2}$

$\frac{121}{49} = { (\frac{x}{4.2} )}^{2}$

$\frac{121}{49} = \frac{ {x}^{2} }{17.64}$

Cross multiply

49(x²)=17.64(121)

49x²=2134.44

${x}^{2} = \frac{2134.44}{49}$

x²=43.56

x=√43.56

x=6.6cm

Therefore, the corresponding median of the other triangle is 6.6cm.