The area of two similer traingles are respectively 9 cm squre and 16 cm squre. Find the ratio of tr corresponding sides?
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Hey there !!
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Let one ∆ be ABC and other be PQR such that there areas are 9cm² and 16cm² respectively.
As we know,
ar(∆ABC) / ar(∆PQR) = (AB)² / (PQ)²
9 / 16 = AB² / PQ²
=> √9 / √16 = AB / PQ
=> 3 / 4 = AB / PQ
Thus, the ratio of their corresponding sides is 3 : 4.
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Let one ∆ be ABC and other be PQR such that there areas are 9cm² and 16cm² respectively.
As we know,
ar(∆ABC) / ar(∆PQR) = (AB)² / (PQ)²
9 / 16 = AB² / PQ²
=> √9 / √16 = AB / PQ
=> 3 / 4 = AB / PQ
Thus, the ratio of their corresponding sides is 3 : 4.
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