Question

The area of two similiar ∆s ABC and PQR are in the ratio 9 : 16. If BC =4.5 cm, find the length of QR.

Answer 1

$\underline{\underline{\Huge\mathfrak{Answer ;}}}$

Dear ,

We have ;-
• ∆ABC ~ ∆PQR

So ,
$= > \frac{area \: of \: (tringle \: abc)}{area \: of \: (tringle \: pqr)} = \frac{ {bc}^{2} }{ {qr}^{2} } \: \:$

$= > \frac{9}{16} = \frac{ {4.5}^{2} }{ {qr}^{2} }$

$= > \frac{3}{4} = \frac{4.5}{qr}$

$= > qr = \frac{4 \times 4.5}{3} = 6cm$

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@ItsDmohit