Math, asked by rohithboorla71, 9 months ago

The area of two triangles are respectively 9sq.cm and 16sq.cm . Then the ratio of the corresponding sides are

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Answered by PRANEETHA
0

Step-by-step explanation:

if two sides are similar then their corresponding sides and angles are equal

assume that ABc, DEF

ar(ABC)/ar(DEF)=AB^2/DE^2

9/16 =ab^2/de^2

(3/4)^2=( AB/DE)^2

AB/DE =3:4

the corresponding sides are in the ratio 3:4

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Answered by Mystreo
0

Answer:

3:4

Step-by-step explanation:

Let the similar triangles be ABC And PQR

And Their Sides Be AB,BC,CA And PQ,QR,RP Respectively

By Using Theo.

Ratio of Areas of similar Triangle=Ratio of Square of their Corresponding Sides

Therefore,

Area of Triangle ABC/Area of triangle PQT=AB^2/PQ^2

9/16=AB^2/PQ^2

√9/√16=AB/PQ

3/4=AB/PQ

3:4=AB/PQ

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