Question

The area of wheel is 7546cm^2 find distence covered by this wheel in 50 revolutions

Answer 1

area of wheel = π r² =7546 cm²
⇒ r² = (7546×7)/22
⇒r² =2401
⇒r =49 cm
now , circumference = 2π r = 2× (22/7)×49
                                  = 308 cm
distance covered in 50 revolution = 308 ×50 = 15400 cm
                                                                            = 154 m

Answer 2

a= 7546cm^2
=> r^2 = 2401cm
=> r = 49cm

distance= no. of rolls * perimeter of the wheel
perimeter = 308 {2*22/7*49}
distance = 15400cm [154m]