The area ofa helow quadrilateral is
(2) 150 cm(b) 180 cm (0) 100 cm (d) none of these
B
С
8 cm
17 cm
8 cm
8 cm
D
A
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Answered by
2
Answer:
b. 180cm is the answer
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Answered by
5
HERE IS UR ANSWER DEAR,
this quadrilateral is in the form of triangle and rectangle ..
so
area of quadrilateral = area of triangle +area of rectangle
area of triangle = 1/2 × b × h
to find height of the triangle
we r using Pythagoras theorem since it is a right angled triangle...
17²= 8² + x²
289 = 64 + x²
289 - 64 = x²
x² = 225
x= 15cm
therefore
=area of triangle
= 1/2 × b × h
= 1/2 × 8 × 15
= 15 × 4
=60cm²
Now area of the rectangle = length × breadth
length = 8cm
breadth = 15cm
so
= 15×8
= 120 cm²
hence
area of quadrilateral = area of triangle +area of rectangle
= 60 + 120
= 180 cm²
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