Question

The area ofa quadrilateral PQRS whose
diagonal Qs = 19.5 cm and offesets on its
alea 5.6cm and lo.6cm is​

Answer 1

Answer:

b=19.5

H1= 5.6

H2= 10.6

Area of quadrilateral

$= \frac{1}{2} (h1 + h2) \times b \\ = \frac{1}{2} (5.6 + 10.6) \times 19.5 \\ = \frac{1}{2} \times 16.2 \times 19 .5 \\ = 8.1 \times 19.5 \\ = 15.795 {cm}^{2}$