Question

The area rhombus is 240 cm² and one of the diagonals is 16 cm. Find the other diagonal.​

Answer 1

Correct question

‣ The area of a rhombus is 240 cm² and one of the diagonals is 16 cm. Find the other diagonal.

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Given:-

⌬ Area of a rhombus = 240 cm².

⌬ One of the diagonals = 16 cm.

To find:-

⌬ Find the other diagonal.

Solution:-

Let length of one diagonal $\sf{d_1 = 16 cm}$

Length of the other diagonal $\sf{d_2}$

Area of rhombus $=\sf{\dfrac{1}{2}d_1.d_2 = 240}$

⠀⠀⠀ ⠀⠀⠀ ⠀⠀⠀ $\sf{\dfrac{1}{2}16.d_2 = 240}$

⠀⠀⠀ ⠀⠀⠀ ⠀⠀⠀ $\sf{d_2 = 30 cm}$

Hence, the length of the second diagonal is 30 cm.

Answer 2

$\textbf{Given Data :}$

$\longrightarrow\textrm{Area of Rhombus = 240 cm \rm{^2} }$

$\longrightarrow\textrm{Length of First Diagonal (d _1 ) = 16 cm}$

$\rule{315}{2}$

$\textrm{Area of Rhombus = 1/2 \times d _1 \times d _2 }$

$\longrightarrow\textrm{240 cm ^2 = 1/2 \times 16 cm \times d _2 }$

$\longrightarrow\textrm{240 cm ^2 = 16/2 cm \times d _2 }$

$\longrightarrow\textrm{240 cm ^2 = 8 cm \times d _2 }$

$\longrightarrow\textrm{d _2 = 240 cm ^2 \div 8 cm = 30 cm}$

$\boxed{\therefore\textbf{ Length of Second Diagonal (d _2 ) = 30 cm}}$