The area under a speed -time graph represents a physical quantity which has the unit of
1 point
m
m^2
ms^-1
ms^-2
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If r is the distance of the charge Q from the point of observation, then
E=14πε
0
r
2
Q
=32 (i)
and V=
4πε
0
1
r
Q
=16 (ii)
Dividing Eq (ii) br Eq. (i), we get r = 0.5m and putting the value of r in Eq. (ii), we get
Q=
9×10
9
16×0.5
=(8/9)×10
−9
C
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