The area under the curve f(x)=3x^2 +6x+9 between x=1 to x=3 is
Answers
Answered by
0
Answer:
The area under the curve f(x)=3x^2 +6x+9 between x=1 to x=3 is 68 square units.
Step-by-step explanation:
To get the area under the curve, we will integrate the equation of the curve between x =1 and x = 3
We have:
∫3x² + 6x + 9
= x³ + 3x² + 9x
Inserting the limits we have:
[x³ + 3x²+ 9x]₁³
(3³ + 3 × 3² + 9 × 3) - (1³ + 3 × 1² + 9 × 1)
= 81 - 13 = 68
The area under the curve is equal to 68 square units
Similar questions