The area under the curve y=x^{2}+2x between the limits x=2 to x=4 is
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y=x4+4x2+2x+4
dxdy=4x3+8x+2
A=∫022x+4+4x2+x4dxA=[22x2+4x+34x3+5x5
]02A=4+8+332+532A=15432=29.06
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ANSWER...xd....
29.06
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