Question

The area under the inequation, y≤ 1 + x is ​

Answer 1

Answer:

given that,

r  

xy

​  

=0.48Var(x)=16cov(x,y)=36

r  

xy

​  

=  

Var(x)⋅Var(y)

​  

 

cov(x,y)

​  

 

⇒0.48=  

16×Var(y)

​  

 

36

​  

 

⇒2.304=  

16×Var(y)

36×36

​  

 

⇒Var(y)=  

2.304×16

36×36

​  

 

∴Var(y)=35.15

∴σ  

y

​  

=  

Var(y)

​  

=  

35.15

​  

=5.92