the areaof aparallelogram is338m if its attitude is twice the corresponding base determine the base and attitude
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AREA of parallegram =338
let the altitude and the base be xand x .but,altitude is twice of base ,altitude =2x
now,
area of parallelogram = base × altitude
338 = x × 2x
338 = 2 x sq.
338 ÷ 2 = x sq.
169 = x sq.
sqrt{169} = x
sqrt{ 13*13} = x
x =13
now,
base = x= 13m
altitude = 2x =2×13= 26m
let the altitude and the base be xand x .but,altitude is twice of base ,altitude =2x
now,
area of parallelogram = base × altitude
338 = x × 2x
338 = 2 x sq.
338 ÷ 2 = x sq.
169 = x sq.
sqrt{169} = x
sqrt{ 13*13} = x
x =13
now,
base = x= 13m
altitude = 2x =2×13= 26m
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